(3^(-3x+4))=1/9

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Solution for (3^(-3x+4))=1/9 equation: 



(3^(-3x+4))=1/9

We move all terms to the left:

(3^(-3x+4))-(1/9)=0

We add all the numbers together, and all the variables

(3^(-3x+4))-(+1/9)=0

We get rid of parentheses

(3^(-3x+4))-1/9=0

We multiply all the terms by the denominator


((3^(-3x+4)))*9-1=0

We move all terms containing x to the left, all other terms to the right

((3^(-3x+4)))*9=1

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